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6t^2+34t+20=0
a = 6; b = 34; c = +20;
Δ = b2-4ac
Δ = 342-4·6·20
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*6}=\frac{-60}{12} =-5 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*6}=\frac{-8}{12} =-2/3 $
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